python3flask实现文件上传功能-创新互联

本文实例为大家分享了python3-flask文件上传操作的具体代码，供大家参考，具体内容如下

# -*- coding: utf-8 -*-
import os
import uuid
import platform
from flask import Flask,request,redirect,url_for
from werkzeug.utils import secure_filename

if platform.system() == "Windows":
 slash = '\\'
else:
 platform.system()=="Linux"
 slash = '/'
UPLOAD_FOLDER = 'upload'
ALLOW_EXTENSIONS = set(['html', 'htm', 'doc', 'docx', 'mht', 'pdf'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
#判断文件夹是否存在，如果不存在则创建
if not os.path.exists(UPLOAD_FOLDER):
 os.makedirs(UPLOAD_FOLDER)
else:
 pass
# 判断文件后缀是否在列表中
def allowed_file(filename):
 return '.' in filename and \
   filename.rsplit('.', 1)[1] in ALLOW_EXTENSIONS

@app.route('/',methods=['GET','POST'])
def upload_file():
 if request.method =='POST':
  #获取post过来的文件名称，从name=file参数中获取
  file = request.files['file']
  if file and allowed_file(file.filename):
   # secure_filename方法会去掉文件名中的中文
   filename = secure_filename(file.filename)
   #因为上次的文件可能有重名，因此使用uuid保存文件
   file_name = str(uuid.uuid4()) + '.' + filename.rsplit('.', 1)[1]
   file.save(os.path.join(app.config['UPLOAD_FOLDER'],file_name))
   base_path = os.getcwd()
   file_path = base_path + slash + app.config['UPLOAD_FOLDER'] + slash + file_name
   print(file_path)
   return redirect(url_for('upload_file',filename = file_name))
 return '''
 
 
 
Upload new File
 

  

   
 
 '''
if __name__ == "__main__":
 app.run(host='0.0.0.0',port=5000)