重庆分公司,新征程启航

为企业提供网站建设、域名注册、服务器等服务

leetcode_组合和

typing import List
class Solution:
def combinationSum1(self, candidates: List[int], target: int) -> List[List[int]]:
#必须要排序 最后的结果可能会有顺序不一样但是元素一样的组合
candidates.sort()
res = []
reslist = []

成都创新互联自2013年创立以来,是专业互联网技术服务公司,拥有项目成都做网站、网站制作网站策划,项目实施与项目整合能力。我们以让每一个梦想脱颖而出为使命,1280元七星做网站,已为上家服务,为七星各地企业和个人服务,联系电话:18980820575

    def dfs(candidates,target,reslist):
        if target == 0 and reslist not in res:
            res.append(reslist)
            return
        if target<0:
            return

        for i in range(len(candidates)):
            print(reslist)
            #这个递归太难,再理解
            dfs(candidates[i+1:],target-candidates[i],reslist+[candidates[i]])

    dfs(candidates,target,reslist)
            function(){ //外汇点差  http://www.kaifx.cn/mt4/kaifx/1749.html
    return res

def combinationSum2(self, candidates: List[int], target: int) -> List[List[int]]:
    candidates.sort()
    # for i in range(candidates):
    res = []
    reslist = []

    def dfs(candidates,begin,target,reslist):
        # for i in range(len(candidates)):
        if target == 0 and reslist not in res:
            res.append(reslist)
            return
        elif target<0 or begin>=len(candidates):
            return
        else:
            # print(reslist,begin)
            dfs(candidates,begin+1,target,reslist)
            dfs(candidates,begin+1,target-candidates[begin],reslist+[candidates[begin]])

    dfs(candidates,0,target,reslist)
    return res

if name== "main":

a = Solution()
print(a.combinationSum1([2,3,6,7],7))

网站名称:leetcode_组合和
文章位置:http://cqcxhl.com/article/pehgoi.html

其他资讯

在线咨询
服务热线
服务热线:028-86922220
TOP