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从键盘输入某班学生某门课的学号和成绩(假设每班人数不超过40人),当输入为负值时,表示输入结束,试编程从键盘输入一个学号,查找该学号学生的成绩
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#include#define N 40
int ReadScore(int score[],long num[]);
int LinSearch(long num[],long x,int n);
int main()
{
int score[N],n,pos;
long num[N],x;
n=ReadScore(score,num);
printf("Total students are %d\n",n);
printf("input the searching ID:");
scanf("%ld",&x);
pos=LinSearch(num,x,n);
if(pos!=-1)
printf("score=%d",score[pos]);
else
printf("Not found!\n");
return 0;
}
int ReadScore(int score[],long num[])
{
int i=-1;
do{
i++;
printf("please input ID and score:");
scanf("%ld%d",&num[i],&score[i]);
}while(num[i]>0&&score[i]>=0);
return i;
}
int LinSearch(long num[],long x,int n)
{
int i;
for(i=0;i
【折半查找】 Binary Search
#include#define N 40
int ReadScore(long num[],int score[]);
int BinSearch(long num[],long x,int n);
int main()
{
int score[N],n,pos;
long num[N],x;
n=ReadScore(num,score);
printf("Total students is %d!\n",n);
printf("input the searching ID:\n");
scanf("%ld",&x);
pos=BinSearch(num,x,n);
if(pos!=-1)
printf("score=%d",score[pos]);
else
printf("Not found!");
return 0;
}
int ReadScore(long num[],int score[])
{
int i=-1;
do{
i++;
printf("please input student is ID and score:\n");
scanf("%ld%d",&num[i],&score[i]);
}while(num[i]>0&&score[i]>=0);
return i;
}
int BinSearch(long num[],long x,int n)
{
int mid,left=0,right=n-1;
while(left<=right)
{
mid=(left+right)/2;
if(x>num[mid])
left=mid+1;
else if(x
提示:mid为输入数组的中间数个数,如果不能整除也没关系,前后两个数都可取
用折半查找效率要高一点
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